28+18n-36+3n^2-12n+12=3n^2+6n+4

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Solution for 28+18n-36+3n^2-12n+12=3n^2+6n+4 equation: 



28+18n-36+3n^2-12n+12=3n^2+6n+4

We move all terms to the left:

28+18n-36+3n^2-12n+12-(3n^2+6n+4)=0

We add all the numbers together, and all the variables

3n^2+6n-(3n^2+6n+4)+4=0

We get rid of parentheses

3n^2-3n^2+6n-6n-4+4=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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